So you are subtracting heights of columns of different liquids? Won't work, if anything, you should multiply them by their densities, not just both by the oil density.
That's just the first thing that caught my attention, doesn't mean there are no other problems, what you wrote is a bit chaotic...
I can be wrong, but it seems to me you are trying to understand the definition in terms of our todays understanding of what the acid is. If so, it probably won't work - I strongly doubt Naunyn thought in terms of H+, more likely he thought something like "when there is chlorine present solution...
No.
Sadly, it is not the first time we have discussion on the efficiency of different techniques used in hand combat. They often end poorly, as the martial art community tends to use terms like "mass", "power", "force" very loosely, completely missing the fact they have a very precisely defined...
Even wiki states: "Reaction with acids (...) removes the silyl group when protection is no longer needed.", so my bet is yes, it is something quite well known.
You don't "make" supercapacitor from normal capacitors, you buy one.
They are not trivial to use, they have a specific, low voltage (around 2.7 V for fully charged), so they require quite a bit of electronics/regulators for both loading and recovering the charge.
I can be wrong, but my understanding is that part of the mounting procedure calls for creating a vacuum in the system. That's to make sure the R-whatever agent that will fill the inner volume is as pure as possible, and not mixed with the humid air that is in all tubes right now. At least that's...
If you are not sure you can always ask here, or in General Discussion, or even just post your question in Classical Physics - just state clearly you are not sure where it fits, and it will be moved by mentors.
Yes, if you don't know physics sometimes deciding where the question goes is...
Endurance flight is about keeping weight as low as possible, so it is probably much wiser to use longer runway (or start from a catapult, even DIY style) than to make model heavier.
Nothing unusual, there is only a limited range of concentrations for which the measurement will work reasonably good (once the concentration gets too high the dependence is no longer linear). Try either more diluted samples or shorter cuvette. The former is rather simple, especially if the...
Looks OK.
The only thing that is a bit incorrect is the fact that if you dissolved 0.5 g in 100 g of water (good approximation for 100 mL) percent concentration of the salt was not 0.5%, but 0.5/100.5*100% (mass of the salt over mass of the solution which is 100g+0.5 g). For such a diluted...
You have answered the question by yourself in the video, which makes me think you didn't really get here looking for help, but just to show your project.
Nice one.
No, it is not correct, and I already pointed you to a reason why it is wrong.
Write reaction equation, calculate number of moles of NaOH, use the stoichiometry to calculate number of moles of H2SO4.