As in my attached pic in OP, θ is between 0 to Pi/2, but I think solving this need more advance mathematical method, which I don't have a clue :confused:
Hope someone with the skills and knowledge jump in and give me a hand
Thanks Villyer, for all your help :smile:
this should be the last equation now?
mgh=mgh(1-sinθ)+0.5Iω2, I=1/3mL2
mgh=mgh(1-sinθ)+(1/2)(1/3)m(2h)2ω2, ω=dθ/dt
g=g(1-sinθ)+(2/3)hω2, ω=dθ/dt
g=g(1-sinθ)+(2/3)h(dθ/dt)2
sorry about the added m into the term for rotational kinetic energy, it's a typo.
as of the moment of inertia I=1/3mL2, assuming m is the mass, L is the length of the object, so the new equation is:
mgh=mgh(1-sinθ)+0.5Iω2, I=1/3mL2
mgh=mgh(1-sinθ)+(1/2)(1/3)m(2h)2ω2, ω=θ/t...
that makes sense, so how do I fix the formula? from wikipedia, I found rotational kinetic energy is E=0.5Iω2, so the new formula is something like:
mgh=mgh(1-sin(θ))+0.5mIω2
and it can be simplied as:
gh=gh(1-sin(θ))+0.5Iω2
Is this one valid now?
if it is valid, can you help me...
the object is simply fall on the floor, from almost up right, due to gravity. there is no other force.
image you try to put a stick up right on the floor, it simply can't stay up right from the moment you take your hand off it.
please ask if i am not making sense, as I am not sure if i...
Homework Statement
find relationship between the angle and time of a tilted falling object
Homework Equations
any that is applicable
The Attempt at a Solution
As seen in picture below, and that's what I have done so far. It's a tilted object, only gavity and the support...