Ignore helicopters people, I'm talking theoretical. A helicopter pushes against a cushion of air held against the Earth by gravity. A theoretical anti-gravity sphere would work without an atmosphere.
Reality and undeveloped knowledge aside, how would you define or express the power requirement of an anti-gravity device?
(This would be another way of posing my question.)
Thanks, I get what you are saying, and I know that's what textbooks say, but it still doesn't sit well.
So let's turn the focus to a theoretical anti-gravity sphere if 1kg mass. No propellers or chairs. If it hovered, how would we define the theoretical power required?
"Theoretical physics doesn't enter into things here. The force due to gravity is (obviously) a force, in units of MLT2, (M - units of mass, L - distance units, T - time units)."
Is this correct? It means that gravity is time dependant.
Guess I'm not looking at the traditional viewpoint but...
What is the calculation that shows how much power is required to offset gravity?
Gravity force is defined with units of kg.m.s-2. How to convert that to Joule.s-1?
I am talking in the context of theoretical physics, not practical engineering like using a rocket or helicopter.
But BTW could...