Recent content by cat_eyes

An air bubble originating from a deep-sea diver has a radius of 1.8 mm at the depth of the diver. When the bubble reaches the surface of the water, it has a radius of 2.6 mm. Assume that the temperature of the air in the bubble remains constant. The acceleration of gravity is 9.81 m/s^2. A)...

Oh! Duh, sorry that makes sense, thanks. :)

Oh, ok thanks

anyone?

but if (76900)Vax = (249000)(769000Vax/24900) then wouldn't Vax get eliminated because the 249000s cross each other out?

Ok, thanks :)

Oh is Archimedes Principle the one that says that the buoyant force is equal to the weight of the fluid displaced?

Ok, so if (Pax)(Vax) - (Pw)(Vax) = (Pp)(Vp) - (Pw)(Vp) then (770000)Vax - (1000)Vax = (250000)Vp - (1000)Vp and (769000)Vax = (249000)Vp right? The only problem is that I don't know how to find the volume now.

[SOLVED] bouyancy problem Homework Statement If a steel ax and a aluminum piston have the same apparent weights in the water which can be written as (Pax)(Vax) - (Pw)(Vax) = (Pp)(Vp) - (Pw)(Vp) where P=rho(density), p=piston, V=volume, and w=water Find the ratio (Wax/Wp) of their weights...

help? I have this same problem for my honors physics class and I was wondering what equation you used to get vx = 9.4?