the full text of the task reads: : a rectangle ABCD and points E, F such that triangles BEC and CFD are equilateral and each of them has only one side in common with the rectangle ABCD. Reason that triangle AEF is also equilateral.
Given a rectangle ABCD and points E, F such that the triangles BEC and CF D are equilateral and each of them has only one side in common with the rectangle ABCD. Justify that triangle AEF is also equilateral.
ad B/equilibrium iodine concentration found during titration ?
reaction of titration: 2 S2O32−(aq) + I2(aq) → S4O62−(aq) + 2 I−(aq)
2 moles of thiosulfate react with 1 mol I2 consumption of thiosulphate...
14,5 ml 0,075 mol/dm3 solution...0,0010875 mol of thiosulfate
equilibrium iodine...
so in the solution of I2 in KI I have to count only with the concentration of the original I2?I don't have to count on the amount of KI?
concentration of the iodine solution...2,5424 g I2 in 100g of solution...25,424 g/dm3 I2...?
1/ iodine stock solution: mixed 2,5424 g I2 and 24,1525 g KI and made up to 100 ml with water
2/ 150 mg active carbon is mixed with 12,5 ml jodine solution from point 1 /
3/ At equilibrium were performed filtration and titration with 10 ml of the filtrate with a volumetric solution Na2S2O3...
Yes thank you...an intermediate product is formed - anion CH3O is bound to the positive carbon, to the negative carbonyl oxygen is bounded Na +? or does sodium bind to chlorine?