Durr... Got fixated on second term of ## \eta^{\rho\lambda} {\partial_{ \mu}}\epsilon h_{\nu\lambda} - \epsilon h^{\rho\lambda} {\partial_{ \mu}}\epsilon h_{\nu\lambda}## (just in case someone of similar density looking up).
Many thanks.
Sorry for gap. I can see Vanhees understands, though it seems to me if ##\partial h## is order ##1/\epsilon## then ##\epsilon h^{\rho\lambda} {\partial_{ \mu}}\epsilon h_{\nu\lambda}## is only order ##\epsilon## but needs to be order ##\epsilon^2## to be ignored in OP equation?
Sorry @vanhees71 I can't get the multiple quote insert to work!Yes, my problem was being sure that ##h^{\rho\lambda}{\partial_{ \mu}}h_{\nu\lambda}## terms were order ##h^2##
It makes sense that ##\epsilon h^{\rho\lambda} {\partial_{ \mu}}\epsilon h_{\nu\lambda}## would be order ##\epsilon^2##...
Sorry, you've lost me. Were you referring to ##g^{\mu\nu}=\eta^{\mu\nu}-h^{\mu\nu}##?
My problem was how to know that the partial derivative (i.e. variation) of a small item was necessarily also small.
if ##\frac{1}{1+x}## is how I should think of ##\partial_{\mu}## here, I'm afraid I need...
@ergospherical, again many thanks.
Self-taught, I realise I don't have enough knowledge of variational (and tensor) manipulations, but there does seem to be a lot of casually presupposed ability packed suddenly into that one bald equality in his notes !
@ergospherical, thanks very much.
I wasn't doubting that logic, just wondering whether my application of index rules was shaky. It seemed to me that the combination of symmetry ## \nabla _{(\mu}V_{\nu)} ## with the dual contraction meant there was no need to rely on symmetry of the...
Contracted but no sum?These look exactly what I think I need to understand to relate tensors and operators, and 'pictorialise':
##R_{\sigma \nu} = \Sigma_X \langle \mathscr{R}(X, e_\sigma) e_\nu, X \rangle##
##\text{Ricci}(A, B) = \Sigma_\alpha \langle \mathscr{R}(e_\alpha, A) B, e_\alpha...
@PeterDonis Thanks again.
Torsion-free: yes, my misapprehension, I got misled by Eq 3.112 in Carroll's book
$$\left[ \bigtriangledown _{\mu},\bigtriangledown _{\nu} \right]V^{\rho}=R^{\rho}\text{ }_{\sigma\mu\nu}V^{\sigma}-T_{\mu\nu}\text{ }^{\lambda}\bigtriangledown _{\lambda}V^{\rho}$$I'm...
@PeterDonis, many thanks for reply and apologies for the lax terminology. References are unavailable, as the end result is my attempted distillate from a blizzard of websites.
I realise ##R^{\rho}\text{ }_{\sigma\mu\nu}\text{ }X^{\mu}Y^{\nu}V^{\sigma}\partial_{\rho}## is a contraction, but...
I'm having trouble with notations and visualisations regarding Ricci curvature.
For Riemann tensor there is variously:
##R^{\rho}\text{ }_{\sigma\mu\nu}\text{ }X^{\mu}Y^{\nu}V^{\sigma}\partial_{\rho}##
##[\nabla _{X},\nabla _{Y}]V##
##R(XY)V\mapsto Z##
##\left\langle R(XY)V,Z...
Thanks very much for the spoon-feeding. My knowledge is patchy, and being 'woolly' on the flurry of notations, it helps me avoid overlooking subtleties and errors applying generalisations, which of course are obvious in hindsight. (Sorry @PeroK, was deficiency in grounding rather than...
@strangerep, sorry, I missed you were separate, so forgot to thank you. Now I am working through your reply, I have a question. In the first equality just quoted, what happened to the ##~ \left( \frac{1}{ \sin\theta} \right)\partial_\theta~## term from the commutator? (Assuming the missing...