Recent content by chocbizkt

true, i found out; px(qxr) = (pxq)xr if you let q=p then px(pxr)=(pxp)xr such that (pxp)=0 therefore its not true statement

thanks i don't know where to go from there

2 questions i have; if true 1. proove that; p x ( q + r ) = p x q + p x r 2. and p x ( q x r ) = ( p x q ) x r where; p = p1i + p2j + p3k q = q1i + q2j + q3k r = r1i + r2j + r3k i have left handside p x (q + r) = (p1i + p2j + p3k)( (q1+ r1)i + (q2+ r2)j + (q3+ r3)k) am i on...

yes well so far for Qn1. i have left handside p x (q + r) = (p1i + p2j + p3k)( (q1+ r1)i + (q2+ r2)j + (q3+ r3)k) am i on the right track?

2 questions i have; 1. proove that; p x ( q + r ) = p x q + p x r 2. and p x ( q x r ) = ( p x q ) x r where; p = p1i + p2j + p3k q = q1i + q2j + q3k r = r1i + r2j + r3k