OK, we let T be the temperature of the object. Then, by Newton's Law of Cooling, \frac{du}{dt}=k(u-20), for some constant k. Let y=T-20. Then \frac{dy}{dt}=\frac{du}{dt}=ky. Thus we are now using the formula y=y_{0}e^{kt}. Since T is initially 72 ◦ C , y_{0}=72-20=52. So, y=52e^{kt}.
This is...