Thanks Klaas! So if I understand correctly, I can compute the RHS using the squeeze theorem.
Since $e^{x^2}$ is strictly increasing on $J = [1,2]$, with absolute minimum value $f(1) = e^{1^2} \approx 2.71$ and absolute maximum value $f(2) = e^{2^2} = e^4 \approx 54.59$.
Using the comparison...
I'm trying to solve the inequality:
$$
\int \limits_0^1 e^{-x^2} \leq \int \limits_1^2 e^{x^2} dx
$$I know that $\int \limits_0^1 e^{-x^2} \leq 1$, but don't see how to take it from there.
Any ideas?