Compute the 9th derivative of cos(6x^4) - 1 / x^7 at x = 0.
Is there an easy way to do this that I'm not seeing? After taking a couple of derivatives, I realized how long this will take if I do it by taking more.
Interesting. Granted, this is an online-based homework program, so I wouldn't be surprised if it had an error in it (although it's been fine so far this semester). When I put in 0 for the first term, it indicated "correct", but when I put in 0 for the second term, it indicated "incorrect"...
For the function f(x) = (10x^2) e^(-2x), I calculated the first term of the Maclaurin series to be 0.
However, for the second term, I also calculated it to be 0, but apparently this is wrong. Shouldn't the second term be f'(x) = 10x^2 * -2e^(-2x) + e^(-2x) * 20x? Or what am I doing...
How would you go about doing this:
\int64x^2cos(4x)dx
The question specifically asks to integrate it by parts, so I integrated it that way a couple of times and came out with some long mess of sines and cosines, but it's not the right answer.
Thanks.