Recent content by chunky

Never mind my solution was wrong although I think that using the equations Vr=0 Vtheta=r*Theta Ar=-r*Theta(dot)^2 Atheta=r*Theta(double dot) However i am unsure as to how to add the trucks acceleration into the solution.

I believe the most appropriate approach would be the conservation of energy ie, T1+V1+U1-2=T2+V2 Then just find all of the relevant pieces of information from the question and subbing them into the equation and solving for the magnitude and direction of the velocity and well as the max flying...

a person slides down a water slide that is 61 m long and has a slope angle of 24 degrees and the end is a ramp with a height of 3.66 m with an angle of 30 degrees to the horizontal determine the magnitude and direction of the velocity of the person when they just fly away from the ramp and the...

The uniform 3.6 m pole is hinged to the truck bed and released from the vertical position as the truck starts from rest with an acceleration of 0.90 m/s2. If the acceleration remains constant during the motion of the pole, calculate the angular velocity of the pole as it reaches the horizontal...

The ball (mass m) strikes the heavy steel plate (mass M) with a velocity of v=30m/s at an angle of 60 degrees with the horizontal. the plate is initially stationary. If the coefficient of restitution is e=0.7 and the spring stiffness is k=155N/m. Calculate the final velocity of the ball and the...