Recent content by cks

Hi, all, I have found the answer from one paper (Molecular Physics, Vol. 103, No. 6–8, 20 March–20 April 2005, 883–890) The adsorption energy Ea at a specific coverage is the difference between the total energy of the adsorbed system and those of the clean substrate and the gas phase molecule...

Hi, all, I find that binding energy (Van der Waals) are different from Adsorption Energy determined let's say from desorption spectroscopy. If approaching from 3/2kT = eV -> then at room temperature, it's approximately 25meV. So, for adsorption to occur at room temperature, the binding...

A light passing through a lens will be focused for a converging lens. However, to look at it carefully, it'll not converge to a single point but to a certain size. The size of it and some fringes surround it is actually a diffraction phenomenon. I don't really understand that the usual...

Just want to thanks selfAdjoint for your simple but great descriptions.

Hihi, I put a photodiode's legs to both the input for a differential amplifier http://en.wikipedia.org/wiki/File:Op..._Amplifier.svg Then, the voltage difference of the photodiode is amplified and its output is then connected to a resistor which is not shown in the above picture. The...

Hihi, I put a photodiode's legs to both the input for a differential amplifier http://en.wikipedia.org/wiki/File:Op-Amp_Differential_Amplifier.svg Then, the voltage difference of the photodiode is amplified and its output is then connected to a resistor which is not shown in the above...

I'm working on phase locked loop. There are two lasers where I'm working at where the slave laser is supposed to get locked to the master laser with a fixed frequency difference between them. In other words, the master laser has frequency f1 and slave laser has frequency f2 and the...

I want to ask, is counter propagating beam written as co-propagating beam? which means two beams that are traveling opposite to each other.

Yes, my friend has math symbolic toolbox. Do you know what is the MATLAB command code for solving this? I have been working for my programme for quite some time, and I can't make it. I'm until this step. I hope I can get it done soon.

I don't have symbolic math toolbox. My MATLAB is just a student version.

Yes, I already have the equations in matrix form. The matrix is not a string, unfortunately. Thanks again.

Thanks, that's a great help. But, I'd like to ask one more question . I mean for putting the equation as string eqn1='2x +3y +4z = -2'; , let's say i have all those equations in matrix A=[2*x+3*y+4*z;5*x+6*y-7*z;5*x-4*y+3*z] I cannot write eqn1 = 'A(1,1)' because Matlab can't recognize it...

I have a lot of these types of symbolic equations where I need to extract the coefficients in front of them in order to get a Matrix. 2x +3y +4z = -2 5x+6y-7z = 5 5x-4y+3z = 1

HIhi, thank you very much.

Hihi, Kerry, You're right, you can write B = [2 3 4;5 6 -7;5 -4 3]; BY HAND and then put into MATLAB so that with a = [-2;5;1]; you can solve by using the notation \ x = B \ a easily. But , MY problem is I want to the MATLAB to recognize A, I mean I want Matlab to get the matrix A from the...