Quote: (Now, assuming you know the initial vertical velocity is some v)
Initial velocity in the y = Vo sin 53.1°
Still 2 unknowns.
I am missing something.
Please be patient with me. I am new to physics and don't understand everything yet.
I have though about it some more.
when it gets launched up Z meters it hits its highest point. At the highest point it is going at a V of 0m/s
From there it begins to drop a total distance of 160m + Z
Falling 160 m it travels for 5.7 s at a V 57m/s If i could only figure out...
Von neumann In the Y direction yes But g never effects anything in the x direction.
If you were to look at the x direction only you would see that v is constant. Meaning no g.
I am attempting to split the launched projectile in the x and y direction
Thanks for the reply voko.
A think i have tried that before.
The canon shots the ball up from 160 m when it come back down to 160m it is the same V as when it came out of the canon.
Witch is the answer they are looking for.
If i knew the V i could solve it. And if i knew any info...
I have been working this one all day. No luck as far.
The question:
A projectile is launched at an angle of 53.1° with respect to the horizontal, as shown in Figure 2-34. ( Ill try to give you a picture of example 2-34) It strikes a target that is 120m away horizontally and 160m below the...