Recent content by coneheadceo

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    Possible friction force needed for a car on a banked curve

    Sometimes it takes a day away to clear the head and get things lined up right. Thanks guys for the help.. Got it straigthened out now.
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    Possible friction force needed for a car on a banked curve

    Okay so from all of the posts and help I just need some help making this unconfusing. I'm not looking for the answer outright but if you guys could reorder the correct equations so I know how to work through it, I know I can walk through it on my own. I'm feeling like I have a brain fart that is...
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    Possible friction force needed for a car on a banked curve

    and this is one of those where the example in the book is for a flat surface and it does not have a solution in the back.
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    Possible friction force needed for a car on a banked curve

    based on how the question is worded I would assume if the car is going to stay on the road is additional force needed, if it is needed how much and in what direction?
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    Possible friction force needed for a car on a banked curve

    I somewhat follow the coordinate system rewrite but am lost on where you got "the component of normal force contributing, we see that it provides ≈2.5 x 10 3 N" and where do I go from here?
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    Possible friction force needed for a car on a banked curve

    So what changes do I need to make to my equations so I address the problem correctly?
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    Possible friction force needed for a car on a banked curve

    Homework Statement A 1200kg car rounds a dry curve (μ= .6)with a radius of 67 m banked at an angle of 12°. If the car is traveling @ 95 km/hr (26.4 m/s), will a friction force be required? If so how much and in what direction? Homework Equations Fn = mg cos 12° ƩFn sin 12° = m (v^2/r)...
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    Gravitational force of three objects on a fourth

    Thank you CWatters! And yes Gab... I am taking a college level intro physics course with an "okay" book. It's been 15 years since I've worked with Physics like this and I'm going to have to review more before diving in. I would have been okay with three objects but four is a bit of a stretch.
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    Gravitational force of three objects on a fourth

    Now I'm confused since the answer in the book is 3.2x10^-8 adding 2.4 + 1.67 +1.67 =5.74 x10^-8
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    Gravitational force of three objects on a fourth

    You would use pythagorean method... A-----B | / | / C-----D so let's say we call "A" sphere that is the 4th sphere... calculating the force of gravity between A and B would give a result of 1.67*10^-8 using g = G (m1m2/r^2) and the same for A - C using pythagorean theorm...
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    Gravitational force of three objects on a fourth

    So do I just use F = (G*m1*m2)/r^2 for each sphere at 90° and F = sin 45°(G*m1*m2)/r^2 for the diagonal sphere and add them all together? doing that I get 3.9 x 10^-8
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    Gravitational force of three objects on a fourth

    Homework Statement Four spheres of equal 9.5 kg are located at the corners of a square of length 0.6 m per side. Find the magnitude and direction of the gravitational field on one by the other three spheresHomework Equations gravity = GM/r^2 with G = gravitation constant, M = mass, r = radius...
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    Angle of fuzzy dice when moving Just want to check

    Homework Statement a pair of fuzzy dice hang from your mirror. While you accelerate from a stop on a horizontal surface to 28 m/s in 6 s, what angle θ does the string make with the vertical? Homework Equations tan θ = Y/X a = ΔV / Δt The Attempt at a Solution Just want a double...
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    Increased acceleration in a pully system

    So am I literally taking (9.8 m/s^2)(0.15)= 1.47 m/s^2 to get the acceleration?
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    Increased acceleration in a pully system

    Homework Statement A window washer pulls themself upward using a bucket/single pulley system. Their weight with the bucket is 65 Kg. a) How hard must she pull doward to raise herself slowly at a constant speed? b) If they increase the force by 15% what will her accelertion be? Homework...
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