ok, so for part a:
m=ro(x), where x=length.
m1=5rx, m2=3r0
F(gravity)-F(friction)=0
so m2g-mv(m1g)=0
(9.8)(3)r0-(9.8)(5.)(0.6)r0-0
3-(5(0.6))=0
And I believe that is how I can prove that the chain starts to slide, but I wanted to makesure I had done that correctly.
But I am...
Hi! I'm studying for an exam on Friday, and I'm stuck on this problem:
A uniform chain of length 8.00m initially lies stretched out on a horizontal table.
A. Assuming the coefficient of static friction between chain and table is 0.600, show that the chain will begin to slide off the table if...