Be careful with your components in the vector notaion. Remeber that vertical components of force vectors have nothing to do with the horizontal with tregards to the algebraic setup.
Okay, here's the first thing that needs to happen. Just as a forwarning, trig will be used to the fullest extent. Remeber that when you want to find the net gravitational force, you don't include the particle that you are ovbserving. The only part that it plays is the distance from the other...
The first step in solving this problem is that your relative appreoach is the right framework to be working in. Remember that because the spring is in contact or rather a part of the problem, conservation of both momentum and energy is applicable. The catch is knowing when each law applies...
I'm not so sure those are right. Though those are the right formulas and such, remember that in the setup where only switch 1 is closed as you say, once the capacitor is charged, there is no more current. Come to think of it, part two and three are both correct, but re-look the first part...
Mkay, well I can see this is for the B exam. I'm taking the C exam, but I'll see where I can help here. For part a of your second question, it looks like you need readjust your forces equation. Remember, the buoyant force is F=mg, where the m is the mass of the DISPLACED FLUID. So you need...
OKay okay,let's try and clear up things once and for all. So in the case of the vertical mass and spring, there are three distinct kinds of energy transformations that are occurring. They are Kinetic energy, gravitational potential energy and elastic potential energy. In the simple case...
Just remember, you need three things. First is an understanding of Newton's laws, which help in organizing the math needed to solve the problem. Second, be ery clear with your labeling of your variables and yor axes. You can call them whatever you want and give anydirection the positive or...
This is an impulse question right here. The formulas for impulse are your best friend in this case. Remember that it's not exactly straitfoward, but requires a little though outside of the definition of Impulse. Hope that gets you started.
Lemme just throw in the Biov-Savart law: Helps you calculte the differential amount of magnetic field produced by a short length of wire...a sort of short hand case of Ampere's law. Unforunately, don;t know too many detail about it, but I know that it's useful in those circumstances. Think of...
Excellent, thanks so much. Turns out that the arrangement calls for maximum power at a valur or R=r/2, which in a way makes sense, t=since it's analagous to a equivalent resistor combination. Just needed a little guiding hand.
So the Problem states as follows: Two batteries, each of Voltage V and internal resistance r, are connected in parallel. This parallel connection is then connected in parallel with a Resistor of Value R.
a) For What Value of R is the Power is maximum?
b) If V=12 and r=.03, what is the...
How's the second two parts coming along, sshow us what you've deon and we'll point you in the right direction with it all, and btw...This problem isn't technically a two dimensional collision problem, but that is of no concern to us now.