Recent content by DarthMatter

I also find that hard to imagine. But if one assumes that the measurement is correct and means that the ball experienced a force equal to the weight of a object with a mass of 2,600 lbs (or the equivalent in Newtons) for a very short time, what else could it mean? I assumed to have gotten out of...

I saw it on TV :D (experiment at 5:50): It's a tiger though, and I don't know how accurate their measurements/estimations were. But I was really surprised how powerful these big cats are!

I think a lion's blow with full force is more likely to be in the order of magnitude of tons than of kg, if you want to compare a weight to the force of the blow.

Nice stuff.

Please let me ask a simple question. Couldn't it be possible that the culture of the Mayans was far from static even before Columbus arrived and that influences from within the American continent shaped the writing system as well? (This was already pointed to here and there in some way in this...

What site are you referring to? I think there may be a misunderstanding. I didn't say they didn't advance scientific fields or that their research focused on a too narrow field. I'm saying the cost of these advancements was probably higher than it needed to be - and there even are fields or even...

Yes, if you drink deadly polluted water because you are so thirsty you die. How much money do you think would have to been invested into the Apollo or other space programs to generate the insight focussed research on cancer has given in the preceding decades? People survive today because of...

What special case? ##-g(x)+c## is not odd in general.

It's like physics: It is generally best to understand the problem as a whole. But it is not always easy to do.

Phew.

##48!## or 48?

If ##f## and ##g## are odd: ##(f+g)(-x)=f(-x)+g(-x)=-f(x)-g(x)=-(f+g)(x)##.

That's very interesting. If I make it into 2100 in a robot body, I'll send all other PF-robot-body-guys a message. My scores at this game range from 16 to 34. Must ... stop ... playing ... now.

Lets look at ##ax = e^{bx}##. Is ##ax## tangential to ##e^{bx}##? ##\frac{a}{b} = e^{bx}\Rightarrow x=\frac{\ln(\frac{a}{b})}{b}##. Such an x exists as long as ##\frac{a}{b}>0##. However, we also need ##{a}\cdot x = e^{bx}\Rightarrow {a}\cdot \frac{\ln(\frac{a}{b})}{b}=\frac{a}{b}## or...

Please let me ask a possibly dumb/basic question. Why isn't it true that shifting a function left and right again (differentially) results in the same function for all functions? Does this have to do with the chosen coordinate system?