So since A= BCD. it wil be brighter. and since the current is split between that then half goes to D then half goes to BC. so that's how you get it. But E would stay the same I believe because it is its own independent pathway...?
When the switch is closed, what happens to the brightness of bulb D? What happens to the brightness of bulb A? Explain your reasoning.
I initially thought it would decrease because current splits between D and BC. But since it is parallel to BC would it increase because the it would be R/2...
So i just took a final and the question was
Arrange the following solvents in order of boiling point.
water 2-methylbut-1-ene cyclohexane
So the answer was Water>cyclohexene> 2-methylbut-1-ene.
I understand by the hydrogen bonding that water is definitely #1. But I can't...
If you lie on the ground at night with no cover, you get cold rather quickly. Much of this is due to energy loss by radiation. At night in a dry climate, the temperature of the sky can drop to -40oC. If you are lying on the ground with thin clothing that provides little insulation, the surface...
Well they are enantiomers. So they would have the same MP? Therefore it will also be 125? But why is the mixture(I believe this would refer to racemix be higher)?
In your context L would be unpure. But I thought D- dextrorotary prefix refers to + rotation and L =levorotary (l) prefix refers to − rotation. Although I don't see how that has anything to do with the question.
How am I supposed to approach this? Thanks!
The melting point of N-acetyl-DL-alanine is 137◦Cand that of N-acetyl-D-alanine is 125◦C. What
would you expect the melting point of N-acetyl-L-alanine to be or is this impossible to predict?
Why?
I thought that to approach this problem all that needed to be done is take the average of...
Homework Statement
What will the affect be on the potential of the cell if salt bridge isn't wetted?
If the salt bridge isn't wetted with KNO3 how would it affect the measured potential of the cell2. The attempt at a solution
So I thought that the potenital will be more negative because since...
No. It just states "calculate the [OH] concentration from the above solution at 50 degrees" But, I am pretty sure that would not make a difference. Correct?