Recent content by flamebane

  1. flamebane

    I know everything to do on this problem except one thing

    I know what the r's mean I just dont really know how I'm ment to get it, would I use the distance formula?
  2. flamebane

    I know everything to do on this problem except one thing

    My strategy is to first find all the potential and kinetic energy of particles A and B, then C. then using the principle of conservation of energy to find V.
  3. flamebane

    I know everything to do on this problem except one thing

    Even though I have all the formulas needed to do this problem, I cant figure out how to get rA, rB and rA' aswell as rB'
  4. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    I converted the net charge from nC to C and then divided it by ε
  5. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    Using Gauss's Law I got 504, which is double what it should be
  6. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    The File that I uploaded is the full problem statement
  7. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    So does that mean I cant use Gauss's Law with Q/e0 ?
  8. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    Q/e0 right? Q would be net charge which would be 4.46*10^-9 and e0 is stated in the question?
  9. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    I would assume that the particle would be at the center suspended above, and as for equations theres: Φ=EA, Φ=EAcosΘ, for flat surfaces theres σ/2e0, E=λ/2πe0r, and I forgot the electric flux for a closed.
  10. flamebane

    Electric Flux through a semi-spherical bowl from a charged particle

    I believe this does has a couple of Calculus aspects to it but I don't really know how I'd find the surface area of inside the bowl. The answer sheet says the answer is 252 with a margin of error of +/- 1
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