Confused, but tried it this way:
Use u-substitution to show that (for y a positive number and x>0)
\int_{x}^{xy} \frac{1}{t} dt = \int_{1}^{y} \frac{1}{t} dt
so, u=t and du=dt
if x=1
t=xy u=y(1)=y
t=x u=1
or
u=1/t and du/ln [t] = dt
if x=1
t=xy u=1/y
t=x y=1
Thanks for...
Here is the question:
Two people start from the same point. One walks east at 3 mi/h and the other walks northeast at 2 mi/h. How fast is the distance between the people changing after 15 minutes?
I have:
dx/dt= 3 mi/h, dy/dt= 2 mi/h, dz/dt= ?
x= 3*.25= .75, y= 2*.25= .50
The instructor...
Here is the question,
Evaluate this limit:
\lim_{x\rightarrow 1} \frac{x^3-1}{x^2-1}
since there is no common factor, this limit does not exist, correct?
Maybe I am missing a basic algebra rule for the numerator to find a common factor.
Thank you.
Hello everyone, I love this site. It has been a lifesaver when completely confused. I am finishing my last year towards a BS in Wildlife Biology. I am very interested in population viability analysis, predator-prey relationships, conservation biology, and all things dealing with management of...
Hey there, I need a little push in the right direction.
Here is the question:
The slope of the tangent line to the graph of the exponential function
y=2^x at the point (0,1) is lim x approaches 0 (2^x-1)/x.
Estimate the slope to three decimal places.
Where I am getting confused is which...
I am going crazy on this problem:
\int sec(v+(\pi/2)) tan(v+\pi/2)) dv
if I substitute u= tan(v+\pi/2)) dv , can I use the product rule to find du= sec(v+(\pi/2)) dv .
Thanks, Todd
Thanks for your help. I only needed to change my calc. to radians to work out the problem. I never had the manual for the calc., and HP only has the Spanish version to download.
Todd
Simple Harmonic Oscillation
Hello, I am new here and wish I had found this forum earlier in the semester. Here is the situation:
A block (mass m=0.75 kg) rests on a horizontal surface (frictionless), attached to a horizontal spring (k=235 N/m). At time t=0, the block is located at the...