Here is my situation:
According to ellipsometry theory the complex reflectance ratio can be expressed as
[PLAIN]http://img255.imageshack.us/img255/2657/68578079.png
where tan(\Psi) is the amplitude ratio upon reflection and \Delta is a phase shift.
On the other hand, as far as I now, phase...
Essential difference I see perfectly. what I need is to describe this difference in terms of Ex, Ey and Ez.
Anyway, now I understand it, thanks for picture ;)
It seems that I understand bt it still is a bit foggy for me. Any further clarification would be greatfully appreciated.
Here is modified image with x, y and z.
http://img232.imageshack.us/img232/2802/0511copy.jpg
Uploaded with ImageShack.us
Let us imagine a surface, with X and Y axes on it and Z axis normal to it.
well, the theory, (in my particular case, some article) says that S polarized light, propagating along the x-directioin possesses only electric field components, Ei, parallel to the surface (||y-direction), i.e...
I'm still trying (yet unsuccessfully) to deal with surface plasmons, and I still hope on your help.
let me start like this:
I find in the review that:
We consider an interface in the xy-plane between two half-infinite spaces, 1 and 2, of materials the optical properties of which are...
After searching through the web, only thing I could conclude and understand is that after several transformation from ejx=cosx+jsinx I come to:
cosx=(eix+e-ix)/2
but, what I can't understand is the equation:
(eix+e-ix)/2=R{eix}
well, the wikipedia says that:
see...
May be it's a stupid question but I can't figure it out.
according to Eulers Relationship:
ej\alpha=cos\alpha+jsin\alpha
on the other hand I have equation:
Vt=V0cos wt
and it can be rewritten as:
Vt=V0ejwt
where V is voltage in AC (see link below)...
Sorry, I can't follow the point.
may be for you it looks as A, B, C, but for me it's far more complex.
can you tell me in more details, what you mean by "If you want plasmons to be generated to the left of a surface then the light coming in from the right must reflect to the right"?
Surface Plasmons ?
Well, to begin with, I am not a physicist and therefore please don't redirect me to some physics tutorials.
now the question:
Why is it necessary for surface plasmon exitation by light that the incident light must have component normal to the surface?
I know that this...
I am not a physicist; not even close to it. so excuse me if I am telling stupid thing but right the next paragraph says that:
"This optical phenomenon is mathematically identical to the quantum tunneling of a particle through a classically insurmountable barrier."
If my logic does not betray...