Hmm... A student who's never had a good teacher though,or is the product of a terrible system may not learn despite his/her best efforts. But, I agree with you to a certain extent. Too many students blame the teachers/the system when they themselves need to be responsibility. But, I'm certain...
Hello, I've been pondering this question for many years now and I've finally believe I've discovered the answer. The answer is to adopt a set of study strategies that force you to deeply ponder physics as much as possible. I'll explain. When many students first start out studying physics, they...
I know that its for boosting minorities in physics & not for giving people with other issues a chance. However I didn't fit purpose and applied anyway. A masters program from here took me in. Just saying it could be an option after he strengthens his foundation. Although the above program does...
Ok thanks! I'll definitely contact him. Another question. I'm looking to transfer there because it seems less competitive than say, Harvard/Columbia. Also, if I do get there and work under him, since he's a world-renounced researcher (one of the highest cited in world), it seems that having his...
I didn't contact him yet. I think that since he's busy (he's one of the highest cited scientists in world has 15 grad students and is professor emertus at Berkley), he won't have time or my just tell me to just apply. Should I still contact him? Other options?
Hello,
I'd like to work in the above named center at the University of Georgia in Athens, Georgia under Dr. Henry Schafer. However, he's a professor in the chemistry department. I'm guessing if I go in the university as a physics graduate student I can't have him as a Ph.D advisor. However, is...
Oh I forgot something:
df/dx = f'(x+vt)*dx;
df/dt = f'(x+vt)*v*dt
So KE + PE = μ/2[(f'2(x+vt)*dx+v2*f'2(x+vt)*dt] = 0.5*μ*(1+v2)*f'2(x+vt)*(dx+dt)
Forgot to add primes in front of f's to indicate derivative.
df/dx = f(x+vt)*dx;
df/dt = f(x+vt)*v*dt
infinitesimal energy = KE + PE = μ/2[(f2(x+vt)*dx+v2*f2(x+vt)*dt] = 0.5*μ*(1+v2)*f2(x+vt)*(dx+dt)
Total energy = ∫0.5*μ*(1+v2)*f2(x+vt)*dx I'm guessing dt goes to zero since we're integrating with respect to space/over entire spring & not time. Is this...
Ok, so I figured out that dψ/dx = dψ/dt. So infinitesimal energy = μ/2(2V2*(dψ/dx)2)dx. Since v2 = T/μ, infinitesimal energy = T*((dψ/dx)2)dx. Now I integrate to get total energy for whole string: total energy = ∫T*((dψ/dx)2)*dx. Limits of integration are ±∞. I don't see how they go from this to...
Homework Statement
There's a string with tension T & mass density μ that has a transverse wave with ψ(x,t) = f(x±vt). f(x) is an even function & goes to zero as x→±∞
Show that the total energy in the string is given by ∫dw*T*((f'(w))2; limits of integration are ±∞
Homework Equations
The...
The Attempt at a Solution
1) ∫-∞ ∞δ'(x)*f(x-a)
2) = ∫δ(x)*f(x-a)dx-∫f'(x-a)*δ(x)dx
3) = f(-a) - f'(-a)
Went from 1st to second by integration by parts
Used integral definition of delta function to go to 3rd part
Made above easier to read