Thank you but how can I apply KCL if all the current calculations sum up to the total of 1.125A as of now, without the need to add anything? I got 0.375A at the 4 Ohm resistor and 0.75A at the one above it (slightly off according to the simulation but I guess it's calculated right) - so we have...
So I rolled the first triangle into something like this:
http://i.imgur.com/EC0HnMl.jpg
Thanks to that I had only parallel resistors and series - I simplified the parallel ones and then had the equivalente resistance of the whole circuit thus getting the first and last amperage. The ones beside...
OK, I almost did it! I transformed it to a star-like shape and calculated everything by looking at equivalent resistors made in parallel and the only thing left is the current beside the 3 Ohm resistor. Could someone please help? So close yet so far - I can't think of any way to transform it any...
Oh, I see. In that case, I guess I'll surrender as we haven't covered anything past the regular simplifying method on our lessons and it seems next to impossible to master all those right methods now, in some half an hour - I guess the prof wouldn't be too mad at anyone not having done that...
So I'm to calculate the current intensities in the places I put the ammeters in (yeah, I reckon one of them is turned around :)):
http://i.stack.imgur.com/PAmmD.jpg
And while I can calculate such things for series or parallel circuits, I was taught I should first try to simplify the...
Homework Statement
Derive the formula for rod's moment of inertia: I = ml2/12
Homework Equations
I = ml2/12
The Attempt at a Solution
The only one derivation I know of is dividing the rod into two parts and then integrating from 0 to l/2. However' I'd love to know if there's some...
Homework Statement
A cycler is going through the winding, cycling on a circle of radius 6m and is slanting with alpha=75^ to the horizontal surface. What's his velocity?
Homework Equations
T=\frac{mv^{2}}{R}
Fc=\mu F_{N}
The Attempt at a Solution
We have two forces on the cycler...
HallsofIvy - OK, thank you. So we get t = (2 (sqrt(5 a+9)-3))/a (the other one is negative so doesn't matter), we plug it into the latter and get (2 (sqrt(5 a+9)-3) so (sqrt(5 a+9)=3 but then... a would have to be 0, which it's not, is it? Where did I make a mistake?
Homework Statement
A man on a boat throws behind him a rock of mass m1=2kg with a velocity of v1=18m/s. The mass of a man with a boat is m_2=90kg. What velocty v_2 will the boat go with?
Homework Equations
v2 = (m1*v1)/m2
The Attempt at a Solution
So I was upsent on the lesson...