Joe could CONFIDENTLY give me the ticket numbers, so he must have eliminated all other possibilities based on my 2 answers. If I had answered yes to both questions, there would be too many possibilities. So... wrong answer :)
10 prisoners are about to be executed. The executioner gives them each a chance to survive, "I will place a little hat on each of your heads, either black or white. All those who can correctly guess the color of the hat they are wearing will be let off, and all those who can't will be killed...
I think many of you have problems understanding my solution (case 1). I shall attempt once more...
First, let's establish the fact that if you are left with 3 untested objects, one of which is too heavy, and you have only 1 weigh left, then it is possible to find out which one is the bad...
I think you don't get my answer. The explanation is very long if I go into full details I think.
Please note that:
1) when you have 3 balls left, and one of them is too light (or heavy), you can find out which is the one with simply one weigh. Point is, you must already know if the bad ball...
Proof of 0.999999999... = 1
Let 0.9999999999... = x
Therefore, we have
10x = 9.99999999999...
10x = 9 + 0.9999999999...
10x = 9 + x
9x = 9
x = 1
x = 0.9999999999999... = 1
Yes it is possible.
Separate the 12 objects into 3 groups of 4.
Weigh 2 groups of them.
CASE 1:
If they balance, the 8 objects are good, and the bad object is in the remaining group.
Use 3 of the good objects to weigh against 3 of the remaining ones.
If it balances, the last object...
I wanted to catch the latest action show with my girlfriend, so I went to buy 2 movie tickets. Walking away from the counter, I bumped into a friend Clever Joe.
Clever Joe was interested to know my movie ticket numbers, but I cheekily refused to tell him the answer directly, telling him...
Hi,
I am new here and has been thinking about this for quite some time...
It is generally accepted that to use electrical devices in countries with AC voltages different from yours will require a separate adapter. But what actually happens in the adapter that renders it unuseable in...