Thank you for the information.
I apologize for the error "Schoenberger -v- Schrodinger. I was recently involved in an industrial accident (compressed air) and have some hearing loss.
Correction: Schrodinger...hope that is right.
I have one college Physics course under my belt some 25...
Thanks.
I watched this program when it first aired and it addresses most of my questions but does not provide the formulas or the answers.
Science Channel - Last night - 8/23/2009 - "Killer Waves"
Science Channel - 9/07/2009 (my birthday-must be some significance there) - "Killer Waves"...
Very helpful, THANK YOU!
From your explanation and formula, it is reasonable to state that a 20' wave is not possible from a 4' sea state.
Excellent. Something in the order of an 11' wave sate would have existed to have created the 20' wave.
Would energy from an underwater current moving...
You're right.
I believe the formula(s) needs to be worked "backwards" to arrive at an answer.
What I mean by sea state is in effect "energy". By energy in this example I mean wave height in feet, a 3' to 4' sea state, 3' to 4' waves = wave energy.
With the linear wave formula I am...
RE: Ocean Waves:
1. Linear Wave Formula - What is the average sea state that is capable of producing a 20 ft. wave?
2. Schoenbergers Wave Formula – What is the smallest average sea state that is capable of producing a 20 ft. wave?