No, my prof hasn't done an example. Probably because there isn't enough time in a 5 week summer session. There are also no examples in my text dealing with non-uniform fields, which doesn't help.
Thanks for the help. I think I can handle this problem from here.
By \vec {E}(\vec r) do you mean this?
The top side of the cube has the dimensions (.3, .3, 0) so \vec {E}(\vec r) would be:
(-5.00 N/C\cdot m)(.3 m)\hat{i} + (0 N/C\cdot m)(.3 m)\hat{j} + (3.00 N/C\cdot m)(0 m)\hat{k} = (-1.5 N/C) \hat{i} + 0 \hat{j} + 0 \hat{k}
Assuming that's correct...
The non uniformity of the electric field in the following question is throwing me off. If the electric field were uniform I'd have no problem.
I assume I would use the following equation to solve for each of the surfaces:
\Phi = \int \vec{E} \cdot d \vec{A}
I'm having a difficult time...