This may sound stupid, but why when I shine a laser pointer at a mirror and reflect in onto another mirror back and forth, the points of light make a parabola when the mirrors are tilted in such a way as to maximize the number of reflections happening? Tilting the mirror further or closer then...
I have a question about why y=(-2)x is impossible to graph and I don't know what to say because I know that with some graph paper and a chart of values I can sure graph it pretty easily but my computer graphing program won't do it. Why not? Why is it "impossible" ?
exactly! that would make sense wouldn't it? But no where in the question, or even in the lesson as a matter of fact, did it mention Io being equal to 1.
Quote from the text : "The Richter scale... is based on a comparison of intensities to Io, which is an earthquake of intensity 0."
Did I just...
I know! :P I don't understand what else it could be though?? No additional info was given in the question and no one else that I have showed this to has a clue of what to do!
ok I got pH2=3.699 after substituting 10-4 for [H+] after working through that. This makes sense since the solution is diluted the pH would be less, no?
An Earthquake measures 6.1 on the Richter Scale. What is the rating on an earthquake that is twice as powerful?
I = I0 × 10M
I-intensity of earthquake
I0-earthquake with intensity of 0
M-magnitude of earthquake on the Richter Scale
So I figured I'd use I1 = I0 × 106.1 to find the...
Theoretically, the universe is expanding uniformly over time, dragging the galaxies along with it, right? That's why we can see the galaxies flying away from each other faster than the speed of light. But I was told they are not technically moving through space but with it. Like drawings on the...
ok right. But if M = log(I/I0) then I = I0 x 10M... would this be the same as... I = I0EM
do you see what I'm saying? Because it would be a lot easier just to take the Io value and multiply it by 10 to the M every time, in such a situation.
A flask contains 500 mL of an acid with a pH of 4. If 500 mL of water is added, what will the pH of the new solution be?
I don't want to know the answer please*
I'm just wondering if it is as easy as adding the two pH's ie. 7 + 4
or do I have to work out the H+ of each ie. 10-7 and 10-4...
yeah I see what I did, it was just a mistake on the first post, but I get it now.
also, just from looking at this question I was wondering:
if M = log(I/I0) then I = I0 x 10M... would this be the same as... I = I0eM
'e' as in exp.