Recent content by gsmtiger18

Homework Statement A long straight wire has a line charge, λ that varies in time according to: λ = λ0e(-βt). A square loop of dimension, a, is adjacent to the wire (at a distance a away from the wire). Calculate expressions for the displacement current at the center of the wire loop and the...

Is there a way to derive that?

Homework Statement Light of wavelength λ = 450 nm is incident upon two thin slits that are separated by a distance d = 25 μm. The light hits a screen L = 2.5 m from the screen. It is observed that at a point y = 2.8 mm from the central maximum the intensity of the light is I = 55 W/m2. a)...

Homework Statement A long, straight wire has a line charge, λ, that varies in time according to: λ = λ0 exp(-βt). A square wire loop of dimension a is located adjacent to the wire at a distance of a from the wire. Calculate expressions for the displacement current at the center of the wire loop...

Yes, I know that. Thank you so much.

The product of the fractions outside the parentheses is 4/n. Since the value of the fractions within the parentheses is less than one, 4/n multiplied by that value is obviously going to be less than or equal to 4/n.

4/n?

They're continuously decreasing, so each successive fraction is smaller than the last. That would suggest that the sequence converges. Like you said, they are not complex or irrational numbers. Every fraction within the parentheses is less than 1. Is that the important part?

Forgive me if I sound irritated, but the whole reason I asked this question is I HAVE NO CLUE WHAT I'M DOING. I chose 4/n because it was what resulted from the terms on either side of the parentheses. I don't notice anything about the fractions in parentheses.

The numerator is constant, and the denominator is continuously increasing. I'm grasping at straws at this point, but could an overestimate be 2/n?

Well, my thinking is that n! becomes infinitely large. That said, I think that since n! is in the numerator, I should look for a value in the numerator which is comparatively less than n! and also becomes infinitely large. However, I'm unsure how the numerator is established. Also, why did you...

That's the problem. I don't have any idea how to do that. At all. All we were told was that we had to know how to do these kinds of problems. It was never taught in class.

I know that 23/2n goes to zero. Would that be a valid overestimate?

Yes, that's how it should look. Again, I'm not sure what it is I'm supposed to be seeing here.

Same thing, only the factorial ends in (n-1) * n and 2 is multiplied by itself n times. I still don't have a clue what that tells me.