Well first define p - I'll give you that p=pcostheta(rhat)+psintheta(thetahat)
So then, N=p x E=((p^2)/(4pie0(2z)^3)*[(costheta(rhat))+(sintheta(thetahat))] X[(2costheta(rhat)+(sintheta(thetahat))]
The N that I gave you can be simplified further - in its simplified form you will get the...
I have attached a rough (very ugly) sketch of what the mirror charge configuration should look like.
E=[p/((4pi*e0)*(2z)^3)]*(2costheta(rhat)+sintheta(thetahat) now your p is going to equal what?
Here's hint number one: where is the image dipole? And did you account for it in your equation of E?
You need to use the method of image charges for this problem, Griffiths explains the topic sufficiently if you need any reference.
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