Recent content by hemang

thanks. i got it. (25.7m/s)t=(18.6m/s)t-208 t=208m/(7.10m/s) t=29.3 seconds

help please- urgent Two cars, A and B, are traveling in the same direction, although car A is 208 m behind car B. The speed of A is 25.7 m/s, and the speed of B is 18.6 m/s. How much time does it take for A to catch B? help me with equations.

t for A: (208m-d)/25.7m/s so, d= 208m-(25.7m/s)t t for B: (208+d)/18.6m/s so, d= (18.6m/s)t-208m (18.6m/s)t-208m = 208m- (25.7m/s)t t=416m/44.3m/s =9.39 seconds what about this?

so, would that be 208-d?

car A: time=(d-208)/25.7 so, d=(25.7m/s)t + 208m car B: time=(d+208)/18.6 so, d=(18.6m/s)t-208 (25.7m/s)t + 208m = (18.6m/s)t - 208m (7.10m/s)t = -416m t= (-416m)/(7.10m/s) t=58.6 seconds Is this right?

I don't get it. could u describe clearly?

I still don't get it. help me further. I will appreciate it.

Two cars, A and B, are traveling in the same direction, although car A is 208 m behind car B. The speed of A is 25.7 m/s, and the speed of B is 18.6 m/s. How much time does it take for A to catch B? Time it takes for A to catch B is speed=distance/time time=distance/speed =208/25.7...

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