I actually didn't know that the apparent weight was Fn but it turned out to be correct. What even is "apparent weight" I thought it was the weight when moving.
Diagram for question 2:
Please check if my work is correct.
Main equation: Fc = Fg - Fn
Fn = Fg - Fc
I assume that: Fn = Fg when stationary
Fg = mg
I divide by 5 because the apparent weight must be one fifth of her weight when stationary
Fg = mg / 5
Fn = Fg
Fn = mg / 5
Now to substitute...
so the I found that the potential energy lost was 4.03g's. Using the law of conservation of energy, that should equal the kinetic energy:
4.03g = 1/2(mv^2)
which turned out to be: 6.2g = v^2 (I'm not going to square root this because we need v^2 in the next equation)
mV^2 / r --> (1.3)(6.2g)...
How am I supposed to calculate the loss of potential energy when I don't have the mass of the planet or the gravitational field strength? On the equation above, I canceled out the mass of the planet but I didn't know if that worked.
I tried that but I'll see if I made a mistake, I probably did. For the other question, do you get 16.2m/s^2 for the gravitational strength? I'm just checking because it seems very big.
Oh wait, I was thinking of the law of conservation of energy wrong. I think I get it now. On one of my other questions, there was a force of friction but this problem is frictionless. So, the GPE1 is for the whole system. thanks :)
Diagram for question 1:
I know the mass, I need Fg.
My work:
Main equation: g = Fg/m I need to find Fg.
Fg= Fc - Fn [Fn = 21 N Fc = ?] {I need to find Fc.}
Fc = ma --> Fc = (mV^2)/ r [Mass = 1.3kg V = ? r = 0.70] {Now I need the velocity at that point where Fn = 21 N (the top of the...