I'm trying to refresh my memory since my high school trig class ten years ago. I understand what ASTC is, what the function looks like, etc. With all due respect, I think you're overlooking what I did.
I don't see why you're restricting the domain to 2\pi when a tangent function has a period...
Wonderful. So you leave out tanx=-\sqrt{3} because of 0\leq x\leq 2\pi but wait, you said it has to be 0\leq x\leq \pi because it's a tangent function.
Then you're left with x=\frac{\pi}{3}+{\pi}n & x=\frac{2\pi}{3}+{\pi}n
Is this right?
Thanks for the help
Homework Statement
Solve for x
Homework Equations
tan^2x-3=0
The Attempt at a Solution
tan^2x-3=0
tanx=\pm\sqrt{3}
I'm not sure what to do after this. I could the tan^{-1}(\sqrt{3})=x or x=\frac{\pi}{3}
But then what do I do with the -\sqrt{3}?
What I said isn't very clear, sorry. I am doing "life tables" on the rates of population changes over time within age groups. e.g., for whatever reason there may be 100K people alive at age 50, and 75K alive at age 49 given the circumstances with their parents at birth, or other factors that...
This isn't really a HW question, so I am posting it here. Hopefully someone will be able to help me, and I'm sure many of you will roll your eyes... I want to return one of my new calculators, but I'm not sure which one I should keep. I own the Casio FX-115ES and Sharp ELW516B, both unopened...
Why are my problems written as "sub x" and "sub 0"
Homework Statement
I am doing population tables in math where x represents age. L sub x represents survivor ship at age x. m sub x represents fecundity at age x.
My question is, why is x always "sub x"? There is a an equation R_0 =...
Don't think of plugging those values of x into |x + 2 | > -1/7. You're trying to find out which values of x make this statement true: 7| x + 2 | + 5 > 4. Try plugging your solution into the inequality for x and then seeing if that proves true.
Think of an absolute value as a distance in that a distance is going to be positive. The statement is true because since you know |x + 2| is always positive, you know |x + 2| is greater than -1/7 no matter what value of x you plug in. Remember it is not an equation, so it even if it said |x + 2|...
x5 - x2 > 0
x2(x3 - 1) > 0
x2(x - 1)(x2 + x + 1) > 0
Solving an inequality would mean to express the solution as a union of intervals. In this case, which values of x will result in a value greater than 0 when plugged into the inequality.