only a doubt, in the calculation of the hydrostatic force of 47 000 kN, the force is vertical, why the surface of the 0.25 m is not considered but is multiplied by the entire surface of the tank? the force does not act vertically at the base of the tube of 0,25 m?
thank you very much for your answer I really appreciate your help, I will try to understand why the result is much lower than the monstrous value we get
because if I multiply it by the area with a diameter of 0.9 meters, the result is a force of 4235 kN
while if I multiply it by the surface of the tank comes a monstrous force of 320 000 kN
the first solution is the one that comes closest to the true result of 11,000 kN
@erobz
this pressure now to get the Force I have to multiply it by which surface? that of the tank therefore 48 m2 or that of the 0.9 m section where the water comes out of the tank?
thank you
@erobz
ok I tried again with the calculation, I eliminated from the equation the factors that are not present in the problem, so z1 / hp / ht / P2 as it is 0.
V1 = 3.02 m / s (speed in the section of 0.9 m) calculated with the flow rate of 1.92 m3 / s
V2 = 39.2 m / s (speed in the section of...
@erobz
I tried to calculate the pressure with the equation but I can't solve it as unfortunately I have two unknowns both P1 that of the tank but also P2 that is the pressure inside the 250 mm diameter pipe. Do you think there is anothe way to calculate the pressure ?
thanks in advance...
ok thank you very much now I try to calculate with this formula, just a last thing sorry
the y in the image here attached (sorry but on the keyboard i don't know how to write it) what it is ? and Z it is the piezometric height right ? in this case would be 100 m the maximum height that the...
ok thank you very much for the formula you are really helping me to solve the problem I am getting closer to the solution, but hp and ht where I find these data because I don't have a pump or a turbine in the problem/hydraulic scheme :)
ok thanks for the answer, then it is not enough to calculate reynolds and determine if the motion is turbulent or laminar and consider the frictions accordingly? ok then of the inviscid fluids, this part of physics I think I have never done it
the part of the problem it's this
To Calculate:
Total force to be applied to the piston to empty the tank in the indicated time, considering the continuous and localized pressure drops (steel tube with very low roughness) and all frictions.
at this point seeing that the result is to you where the force is much greater than the result, it makes me think then that I was wrong and the tank at the top is open, but heck it is not written anywhere that it is open on the exercise and also from the scheme that I have copied you can see...