Homework Statement
Consider a mechanical car jack. To change a wheel it may need to lift a load of 2000N. Suppose that one rotation of the screw raises the car by 10mm. You apply a force to the end of the lever, 0.5m long, through a full circle. The jack is only 40% efficient. Calculate the...
Hmmm, after looking at several past papers, it doesn't seem as if they would ask you anything like that. But be careful anyway, they do randomly throw related things in there.
Homework Statement
a) n[SIZE="5"]Ʃ[SIZE="5"]r2(r-1)r=1
Homework Equations
Using the summation series formulae...
The Attempt at a Solution
So far I have got:
r2(r-1) = r3-r2
Ʃr3 = \frac{1}{4}n2 (n+1)2
Ʃr2 = \frac{1}{6}n(n+1)(2n+1)
Therefore,
Ʃr3-r2 = \frac{1}{4}n2...
Each cell will last... 2300mA shared by 120 mA ... so, 19.2 hours. And that's the right answer in the back of the book... wow. Hmm. Thanks! That is right isn't it? The textbook isn't always necessarily correct.
A 1.5V rechargeable cell is labelled 2300 mA h. This means that it can supply the equivalent of 2300 mA for one hour.
b) How much energy does the cell store in:
i- mWh?
ii- J?
and c) How long can four cells, connected in series, light the bulb?
for b) i- I got: W = V x Q, so W = V x I...
1) A thermistor is connected through a switch to a 12V power supply of negligible internal resistance. When the switch is closed, the initial current in the circuiy is 14mA. A few minutes later it has risen to a constant 20mA.
Does the thermistor dissipate more power initially, or after it...
Hi, I can do Dijkstra's Algorithm alright, but I always have problems with questions which have some relevance to the "Order of the Algorithm".
For example, in the Further Maths, Decision 1 (OCR) textbook:
8) Suppose you purchase a new computer which is 100 times as fast as your old one...
Okay, thank you. I understand that, I'm just not sure how to get a ratio from that, with no other information... I'm not even sure if I need to work out a ratio actually. Oh well, thanks anyway.
The resistivity of Aluminium is twice that of copper. However, the density of Aluminium is one-third that of Copper.
a) For equal length and resistance, calculate the ratio:
mass of aluminium/mass of copperI'm thinking, the density ratio (Al:Cu) is 1:3 ...and the resistivity ratio is 2:1 ...so...