Recent content by i_love_space_and_eng

Okay so I plugged it all in and got this: (2/5)m(r^2)(a/r)=(((m1g)-(m1a))-(m2a))R I plug in all the correct numbers but the issue is I still get the wrong answer. Did I write my equation correctly? Should I be getting the right answer and I am probably doing a math error?

I=(2/5)mr2

It will be 6.125*10^-5kgm^2

Okay, so this is what I set up. I(a/r)= ((m1g-m1a)-m2a)R Does that look correct? I substituted a/r for α .

Alright... so how would we go on to find the "a" without the T1 and T2?

Sorry, yes, I see how it is counterclockwise!

Hm... Okay, they actually do make a lot of sense! My only question is, for the m_1a=m_1g-T_1 equation, what would a be? Because isn't the acceleration of the weight dependant on gravity?

Alright, so for the weight: T1=mg For the cart: T2=ma For the pully, Ia=T1+T2?

Okay... For T1, it would be clockwise. and for T2, the same.

Alright, here is my best attempt. I am trying to do what you have stated, but I am not sure how without equaling it to something. But here it is: Force balance on cart: T2 only, because no other force is acting on the cart. For balance on weight: T1-mg Moment balance on pulley: I'm a little...

I took pictures so it could be easily seen next to the figures. I've typing out otherwise when I was first told.

Alright, I think I have that done. Please see below.

Great. Okay, so here I have drawn out the fbds for all three. Is this correct?

I actually think I found a and it makes sense... Now here is my work for (b). Σt=Ia T-mg=(6.125*10^-5kgm^2)a T-3.92N= (6.125*10^-5kgm^2)a Not sure how to find T though... Did I even set that up correctly? Any advice on where to go from here?

I actually think I found a and it makes sense... Now here is my work for (b). Σt=Ia T-mg=(6.125*10^-5kgm^2)a T-3.92N= (6.125*10^-5kgm^2)a Not sure how to find T though... Did I even set that up correctly? Any advice on where to go from here?