Recent content by Imabuleva

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    Is Infinite Work Possible in a Frictionless Vacuum?

    Work-energy theorem: The work done on a macroscopic system is equal to its change in kinetic energy. Infinite work would require an infinite change in kinetic energy and thus an infinite kinetic energy, which means either an infinite mass or an infinite velocity. Both possibilities are...
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    What is the significance of the constant G in Newton's gravitation formula?

    I'm beginning to think Bobie is trolling...
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    Can the Energy of a Photon be Expressed in h/s?

    Yes, that should say, "hbar still has the same dimension as angular momentum." By angular momentum space, I mean that our quantities will be divided by a factor of h. If the energy of a photon was once h*f, it will now just be 2*pi*f. So energy has dimension of inverse time, whereas it...
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    Heavier object has higher inertia

    All macroscopic objects will maintain their velocity unless acted upon by an outside source. In the case of the car driver and the car, the car driver's torso isn't bolted to his seat. It is free to move independently from the car, so he will maintain his velocity as the car accelerates around...
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    Can the Energy of a Photon be Expressed in h/s?

    In Planck units, we define hbar to be 1. In this case, hbar still has units of angular momentum, but we're now working in angular momentum space.
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    Can the Energy of a Photon be Expressed in h/s?

    The unit is part of the number, Bobie. When we say 0.51 MeV or 5 J*s, what we mean is multiply Joule times second times 5 or 0.51 times Mega-electron-volt. 0.51 means nothing without multiplying it by Mega-electron-volt.
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    What is the significance of the constant G in Newton's gravitation formula?

    You can use Newton's second law for columb attraction, an assumption of quantized angular momentum, and a classical energy balance of kinetic and potential energy to derive the Bohr radius, namely: Newton's second law: ƩF = m*v2 / r = k*q2 / r^2 Quantized angular momentum: m*v*r = n*h /...
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    Does nature behave according to the right hand rule?

    Nature abhors a change in flux (at least when it comes to E&M). Nature will "create" electric currents such that the change in magnetic flux through all open surfaces is zero. This is, of course, the premise behind all modern electricity generation. Spin giant magnets near wire loops or wire...
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    What is the significance of the constant G in Newton's gravitation formula?

    Just to clarify, the force would have a value of 6.67*10^-11 N. Because G has a value of 6.67*10^-11 m^3*kg^-1*s^-2, G is not the actual force. It's just the constant of proportionality that relates the magnitude of the gravitational force to the geometry of the system.
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    Does the vacuum of space have finite electrical resistance?

    A true vacuum would have infinite electrical resistance because there is nothing to carry the current. Even interstellar space is far from a true vacuum though.
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    How can objects have negative potential energy at 0 height?

    Negative potential energy is actually essential for bound systems. Any system on earth, for instance, will have a negative gravitational potential energy. A bound electron to a hydrogen nucleus has an energy of -13.6 eV. And so on.
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    How can objects have negative potential energy at 0 height?

    The ball falls because its potential energy becomes more negative as it is converted to kinetic energy. That is, the total energy of the ball stays the same.
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    How can objects have negative potential energy at 0 height?

    The way conservation of energy works for macroscopic objects is kinetic energy added to potential energy is always constant (conservation of energy, of course). So the potential energy of an object can be any arbitrary value and the kinetic energy will compensate depending on how you define the...
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    Photon-proton/ proton-electron interactions

    Hi, jitbell. I replied because the topic is extremely interesting. I apologize that it's old.
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    Photon-proton/ proton-electron interactions

    I just wanted to add my two cents. Think about this classically as if you were to jump in the air. Is it the earth-you system that is in an excited, unstable state while you are in the air? Or is it just you that is in an excited state? Remember that due to Newton's third law when you fall...
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