Recent content by jacy

  1. J

    Trig problem cos (arctan 5/12)

    Thanks everyone for helping me out.
  2. J

    Finding X & Y Intercept of y= cos(e^(-x) + 2)

    Thanks everyone, so there are finite number of x intercepts since no range is given.
  3. J

    Finding X & Y Intercept of y= cos(e^(-x) + 2)

    Thanks pizzasky and VietDao29. No range of x values is given. (e ^ {-x} + 2) = \frac{\pi}{2} (e ^ {-x} ) = \frac{\pi}{2} - 2 {-x} = \log \frac{\pi}{2} - 2 So if i substitute the value of -x in the equation i get cos(pi/2) = 0
  4. J

    Trig problem cos (arctan 5/12)

    Thanks, should the unit be the length of the sides, since 12/13 is not an angle.
  5. J

    Finding X & Y Intercept of y= cos(e^(-x) + 2)

    cos function is zero at 90 degrees. How does that help.
  6. J

    Trig problem cos (arctan 5/12)

    am getting 12/13, am i correct
  7. J

    Trig problem cos (arctan 5/12)

    I have to calculate this without using the calculator. cos (arctan 5/12) So far i draw a triangle and i have the opposite side to be 5, adjacent to be 12, and hypotenuse to be 13. Please suggest me some hint, thanks.
  8. J

    Finding X & Y Intercept of y= cos(e^(-x) + 2)

    Hi, I have to find x and y intercept of this function y= cos(e^(-x) + 2) This is what i have done so far, to find the x intercept i put y= 0 0= cos(e^(-x) + 2) can i use Cos (A+B)= CosA CosB - SinA SinB here if i use that then i get 0= cos e^(-x) cos2 - sin e^(-x) sin2...
  9. J

    Can I use integration by parts recursively on this?

    Can this \int (xe^x) \left[\frac{1}{(x + 1)^2} \right] dx = (xe^x) \left(-\frac{1}{x + 1} \right) - \int \left(-\frac{1}{x + 1} \right)[e^x(x + 1)] dx be further simplified to \int (xe^x) \left[\frac{1}{(x + 1)^2} \right] dx = \frac {e^x}{x+1}
  10. J

    How can I calculate the rate of change between a rising balloon and a cyclist?

    Thanks orthodontist for ur help, am getting the answer
  11. J

    How can I calculate the rate of change between a rising balloon and a cyclist?

    I used pythagorean theorem to get 15.81. I was thinking 15 to be the base and 5 to be the adjacent side. Y= 45 ft high only when the cyclist is right under it. As the cyclist is moving away the balloon keeps on rising so the y value is changing. Balloon is rising at the rate of 5 ft/s, so...
  12. J

    How can I calculate the rate of change between a rising balloon and a cyclist?

    Thanks for replying. In this problem since its given to us that the cyclist is traveling at 15 ft/s, so in 3 seconds he will cover 45 ft and this will be the value of x. Now i have x, and y so i can find s and that will be s = 63.64 ft. Now i can plug everything in the equation ds/dt = 1/s...
  13. J

    How can I calculate the rate of change between a rising balloon and a cyclist?

    Hello, This is what am trying to solve A balloon is rising at the rate of 5ft/s. A boy is cycling along a straight road at a speed of 15ft/s.when he passes under the balloon it is 45 ft above him. How fast is the distance between the balloon and the boy increasing 3 seconds later...
  14. J

    Strategies for Solving Antiderivatives: Tips and Tricks for AP Calculus Students

    Can we solve this \int {\frac{{x^2 }}{{\left( {1 + x^2 } \right)^2 }}dx} using partial fractions
  15. J

    Double Integrals Tutorial: Finding Volumes & Polar Form

    Hello, Can someone suggest me some tutorial on finding volumes by double integrals, and double integrals in polar form thanks. I have a hard time understanding these topics.
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