Recent content by Jessica8956

So total mechanical energy = gravitational potential + kinetic energy + elastic potential The gravitational potential is mg x height Which is 4(9.81)(0.5) = 19.62 JoulesThe elastic potential is (1/2)kx^2 Which is (1/2)100x^2 = 50x^2The kinetic energy is (1/2)mv^2 Which is (1/2)4v^2 =...

Thanks for the reply :) I'd say it loses gravitational potential energy and gain kinetic energy. So goes towards kinetic. The question is using a string and not a spring if that makes any difference?

1. Find an expression for the total mechanical energy when the string is extended and find the maximum distance that the particle falls in terms of g Unsure 3. My attempt at solutionHi :-p Here is the question I am looking at http://imgur.com/a6T8zH7I take the datum as the fixed point so...

I thought that was the position vector for W As I thought the line OA was ​\sin \alpha(i) \sin \alpha(j) and as the length was 2L it was half that as I assumed it was in the middle. I'm a bit lost with this so I hope that makes sense :blushing:

Thanks NascentOxygen We had a supply teacher who gave us questions like the one I am stuck on. They only have a list of multiple choice answers to choose from. Sadly that teacher was only there for a week and my regular teacher said to not worry about it as it is not relevant to what we're...

Thanks for the reply :) So part one becomes {​T} = W(-\sin \alpha(i) +\cos \alpha(j))/2 and part two ​-mgL\sin \theta(k) How does that look?

Sorry about that, I have added the questions now :redface:

1. Finding tension force and torque (details attached) http://imgur.com/cZLG9xP 2. please see attachment http://imgur.com/cZLG9xP 3. For part 1). I get ​{​T} = -\sin \alpha(i) +\cos \alpha(j) is this correct? (Where T is the tension force) For part 2). I am...