Recent content by joeycyoon

Get it clearly! Thanks for the explanation through all these! :thumbs:

Its 1.2 kg! One more to ask, to find the x-component which using cos theta, we use the theta as the value from positive x-axis right?

Is my force vectors correct? Then the components of x will be negative and positive, which will sum up to zero.

Is it means one of the magnitude acting on it is negative? Seriously, I don't know how to sketch the force vectors :confused:

Emm the m1 on top of the triangle and on y-axis, m2 and m3 lie on x-axis, which m3 at the left and m2 at the right.

Homework Statement Three particles with masses m1=2.5kg, m2=1.2kg and unknown mass m3 are placed at the corners of an equilateral triangle of side 30.0cm. If the resultant force in x-direction acting on m1 is zero, find the net force acting on m1. Homework Equations F=(Gm1m2)/R^2...