Oh it was supposed to be L not R.
I=[(1/12) * (1.2) * (1.6^2)] + [(2) * (.4) * (.4^2)]
I=.384
KE=W=(.5)*(.384)*(25^2)
W=120
Does this look good?
Thank you for your help!
Okay so I could say that the change in kinetic energy is equal to the work done on the rod by the torque.KE_rotational=.5 * I * omega^2
F=ma
T=m * omega^2 * r
100=(.4) * (omega^2) * .4
omega=25 rad/sec
Not sure if I found omega correctly. This is the max radial velocity before the string...
I=(1/12)MR^2+2mr^2
So do I use work = torque * theta to find work in this situation?
F=ma
F=m * omega^2 * r
100=(.4) * (omega^2) * .4
omega=25 rad/sec
F=ma
F=m * R * alpha
100=(.4) * (.4) * alpha
alpha=625 rad/sec^2
omega^2 = omega_0^2 = 2*alpha*theta
theta=0.5 radians...
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