Here's the problem...
I am to build a simple windmill (small scale) to lift an x amount of weight twelve inches above the base plane. The required amount is to lift 200 grams, 12 inches in 2 minutes or less. The materials are to be mostly recycled; however, I am alotted $15 to buy any new...
A circular disk of fixed radius r is used in a humidifier, vertically. It is partially submerged in water and rotates on its center. The goal is to determine the height above the water, h, at which to fix the center so that the exposed wet surface area is maximized.
1. Find the surface area...
the disk is vertical... and so far i have the following...
1. Dry Area = pi*h^2
2. Wet area = pi*r^2 - pi*h^2
3. (acos(h/r))/2 * r^2 = sector area
4. sqrt(r^2-h^2)*h = area of triangle
im working on 5 being the wet area - (sector area - area of triangle)...
and this is a challenge problem...
I seem to have down 1-4 on this question but I am struggling on the rest... any help??
A circular disk of fixed radius r is used in a humidifier. It is partially submerged in water and rotates on its center. The goal is to determine the height above the water, h, at which to fix the center...