Recent content by Kallum

Thank you for your responses, so I should do α = 41.5/15.7 to break it down to seconds and then use α = 2.66 rad/s as my value for acceleration? That then gives me an answer of 524 rad. This seems more reasonable!

The question: A wheel was rotating at 12.5 rad/s when a torque was applied for 15.7 s. The angular velocity increased to 54.0 rad/s. What angle did the wheel turn through in that time? My Solution: theta = Wo*t+1/2*a*t^2 = (12.5 rad/s)(15.7)+(1/2)(41.5)(15.7)^2 therefore, theta =...