Recent content by KEØM

  1. K

    Solving for Stress and Strain in Three Dimensions

    Thank you for your help steamengine, I was able to solve the problem by finding the inverse matrix using the method of determinants and cofactors. Thanks again for your reply.
  2. K

    Solving for Stress and Strain in Three Dimensions

    Homework Statement Knowing that the stress and strain for an isotropic media can be related with the following expressions: \sigma_{xx} = (\lambda + 2\mu)\varepsilon_{xx} + \lambda\varepsilon_{yy} + \lambda\varepsilon_{zz} \sigma_{yy} = \lambda\varepsilon_{xx} + (\lambda +...
  3. K

    Exploring Flying Objects: Volume & Surface Area

    HallsofIvy, thank you for your reply. So to better describe the volume of any object could be better described using the following equation: V=C(l_{1})(l_{2})(l_{3}) , where C is a dimensionless constant and l_{1} l_{2}, l_{3} are the lengths of the object. In the same manner we can...
  4. K

    Exploring Flying Objects: Volume & Surface Area

    Homework Statement Suppose we consider different flying objects, and that each object is characterized by a linear dimension l. Part A: Use dimensional arguments to show that the volume V scales with size as V \sim l^{3} and that the surface area scales as S \sim l^{2}. Part B: Show...
  5. K

    Potential Difference with Series and Parallel Resistors

    Hi thebert010, Just as a point of clarification for me, what is the relationship between R1 and R3 and R2 and R3? Or in other words, are R1 and R3 in parallel or series and what about R2 and R3? Thanks, KEØM
  6. K

    Magnetostatics: Magnetic Vector Potential

    OK. Thanks again for all of your help nickjer.
  7. K

    Magnetostatics: Magnetic Vector Potential

    Thanks for your reply nickjer. I think I got it. So because +I flows in the positive direction it must be negative and the opposite must be true for the wire with -I. One more question: For problem 4 on that document it says, Problem Statement The wires are now very close to each other...
  8. K

    Magnetostatics: Magnetic Vector Potential

    I know from just looking at the answer that the -I current must be in the positive z-direction and the +I current must be in the negative z-direction but I don't know why.
  9. K

    Magnetostatics: Magnetic Vector Potential

    I now have a question concerning the third problem on that page attached. Problem Statement: We consider now two wires of axis (O,z) and separated by the distance (2a). The currents in the two wires are +I and -I (see figure). Show that the expression of the magnetic potential vector...
  10. K

    Magnetostatics: Magnetic Vector Potential

    Thanks! I really appreciate the help kreil and nickjer. KEØM
  11. K

    Magnetostatics: Magnetic Vector Potential

    Thanks for your reply nickjer. So because A is a function of only r then all other derivatives go away and because it is only in the z direction then all other components are equal to zero. This then allows me to let -\frac{dA_{z}}{dr} = \frac{\mu_{0}I}{2\pi r}. Is there anything else I must...
  12. K

    Magnetostatics: Magnetic Vector Potential

    Homework Statement Give an expression for the magnetic field and show that a magnetic vector exists such as \vec{A}(P) = A(r)\hat{z} and \vec{B}(P) = \vec{\nabla} \times \vec{A} For the infinite wire shown in figure 1. Here is a link to the figure and problem statement. The problem is the...
  13. K

    Solid sphere inside a hollow sphere.

    Although I am not the original poster, I got mine from the textbook "Physics for Scientists and Engineers" by Randall D. Knight. Sorry if that is not much help.
  14. K

    Conductivity of a set of layers

    Here is the link to the file which contains my worksheet. The picture that describes the configuration of the layers is at the bottom of the page. https://docs.google.com/fileview?id=0B70CA0-G-UYMM2Y3YTRiZjQtNTg1ZC00N2M3LTliODEtOTBjZGYzZmMzZDE4&hl=en" Thanks again, KEØM
  15. K

    Conductivity of a set of layers

    I did some thinking and I think I got it. If I manipulate \vec{j} = -\underline{\sigma} \vec{\nabla}V into V = IR by letting \nabla V_{x} = \frac{\Delta V}{\Delta x} and \nabla V_{z} = \frac{\Delta V}{\Delta z} then the magnitude of my first equation will become j =...
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