i guess i did it right..
i knew the physics of this problem. but i couldn't figure out the algebra.
greatly appreciate your algebra lesson. thank you very much.
Ymax = Voy^2/2g.
sub in and i get
2sqrt(2gYmax/2) to V0y-sqrt(2gYmax/2)
sub in V0y
and i get
2sqrt(2gYmax/2) to sqrt (2gYmax) - sqrt (2gYmax/2)
some algebra help... how you simplify what's in bold...
if I'm doing it right... i get 2 to 1 ratio?? that doesn't sound right.
ya but t1 is time from bottom to middle. the question asks for 2t2/t1 not t2/t1. but anyways, that's technical... no big deal.
wouldn't using vf^2 = vi^2 +2as make this more complicated than it is??
i already got a ratio of 2Vymax/2 to Voy-Vymax/2
there is a way to simplify that?? by...
An athlete jumps vertically. treat athlete as particle and Ymax is the maximum height above the floor the athlete achieves. To explain why he seems to hang in the air, calculate the ratio of the time he is above ymax/2 to the time it takes him to go from the floor to that height.
we get 2...
1a) lands at end of the rod.
1c) conservation of mechanical energy??
4mgh = 1/2 I w squared??
can you type that out LaTeX for me?
2) torque = rF
Force of tension - m1g = m1a1 = -m1a
Ft-M2g=m2a2 = m2a
force on wheel (i'm stuck here)
2c) do this problem as a system??
3) gravity acts on the...
1. a bee of mass M alights (lands softly) on a thin horizontal rod of mass 3M and length l which pivots frictionlessly about its center.
a) what torque did it exert
b) angular acceleration of rod when bee lands.
c) maximum angular velocity when bee reaches LOWEST point?
try:
a) torque =...