Recent content by KrNx2Oh7

I'm reviewing transformers and I have some confusion over the current s is for secondary and p is for primary I know that Vs = Vp(Ns/Np) and Ip = Is(Ns/Np) So when you have a load across the secondary terminal you get your current through Vs/Rload. But does this mean for current in...

Cool that was VERY helpful. Let me see if I understand everything. C1 and C3 block the DC signal and only drop AC voltage slightly since the impedance is low for the capacitors at higher frequencies (Xc= 1/-jwC) For C2 it lowers the voltage seen at V+ because it's impedance is also small...

So this is the op amp I am looking at and I have a few questions, not entirely sure how to ask them, but I'll ask more as I find out more http://postimage.org/image/i228xrkj7/ http://postimage.org/image/i228xrkj7/ So the capacitor C1 and C3 are used to block DC, but when you add these do you...

So apparently there are two types of Vth for a MOSFET http://www.sdram-technology.info/threshold-voltage-measurement.html How can I tell the saturation apart from linear? Right now I am simulating a voltage sweep (on the Gate) of a transistor and the sim results give a saturation and a linear...

Ok so I'm reviewing npn transistors and here is what I am looking at http://postimage.org/image/sdywponvv/ Now the book I bought says Ib = (VE + 0.6V)/R1 I have no idea why it would be that Isn't it suppose to be (Vcc -0.6V)/R1 for Ib The transistor is definitely on as emitter is grounded...

I feel like I'm asking too specific questions Is there some general set of equations I can look at to apply? I have a lot of different types of ICs so I wouldn't want to bother people with a 100 specific questions last specific question: It says for the logic gate that the output...

ok thank you for the help so far So I only need to consider ICs that are above 100mW so I am thinking after looking at spec sheets that the AND gates have very low Icc around uA and Vccs are around 3-5 V and since no output currents are considered these would be well below 100mW right Now...

If I have a positive power rail and negative power rail both Vcc do I use 2*(Vcc*Icc) to get the power Also when the Vout of the voltage regulator is attached to a power supply I have to find the current for every other part of the circuit that is conncected to that power supply correct? Is...

So for op amps and logic gates its only Vcc*Icc found in the schematic? I thought I had to consider the output for let's say an and gate. Don't I take load current and multiply by logic high and add to load current * logic low. Did you mean that there is no Io consideration for op amps and...

I've been looking over how to find power dissipation for voltage regulators, op-amps, comparators, logic gates, and amongst other things. Ive looked at some resources and I'm not getting what each variable means. From what I understood so far I've seen PDstatic = Vcc*Icc where Vcc and Icc...

No current flows from the "15V circuit" to the "28V circuit" since there is no return path...so they do not affect each other like you said So the Vout I'm looking for is the voltage drop of R3||R2 and the right side doesn't affect anything? Also how did your first drawing with all the grounds...

I see that the 28V only affects R4. For the Vout, just to verify it is the voltage across whatever the 28V R2 R3 R4 is reduced to correct? Was the source transformation method I did plus voltage divider afterwards not correct?

Also I'm thinking I'm not getting the concept of ground then Aren't all grounds connected since they all are 0.

step by step this is what I did. 28V/(R2+R4) is current source in parallel with (R2+R4) reduce the resistors to R3||(R2+R4) change it to voltage source of 28(R3||R2+R4)/(R2+R4) and the resistor is (R3||(R2+R4)) so its 15V connected to R1 connected to other resistor connected...

So far I understand it as this: 1) Vin at gate provides current to go into the base of the NPN 2) This turns on the bottom BJT allowing C to E current to flow (the amplification) now looking at my drawing,,does the current from the left Volt source split itself between the collector of NPN and...