Recent content by Libohove90

-i^2 = 1, not -1. This makes (-i hbar)^2 not equivalent to (hbar / i)^2

Homework Statement There are two ways to write the momentum operator, p = (-i hbar d/dx) and p = (hbar / i)d/dx. How do you go from one to the other? Homework Equations The two I gave above. The Attempt at a Solution I tried to see if -ih = h/i by squaring both sides, but one came out...

I was hoping I can get around the long calculations lol

Gradient of a dot product identity proof? Homework Statement I have been given a E&M homework assignment to prove all the vector identities in the front cover of Griffith's E&M textbook. I have trouble proving: (1) ∇(A\bulletB) = A×(∇×B)+B×(∇×A)+(A\bullet∇)B+(B\bullet∇)A Homework...

Simply put... Net work = 1/2 kx^2 - mgy where x is the displacement from the initial equilibrium position to the final position and y is the vertical displacement due to gravity. You see that the work done on the mass by gravity is mgy...thus gravity helps you. Thus subtracting the total work...

The equation governing the motion of the ship is x = xo + vt. The equations governing the motion of the torpedo are x' = vx' t and y' = vy' t. I need to set x = x', but before I do that I must solve for t in the third equation and that is t = y' / vy'. I plug this equation for t in the x =...

Homework Statement I figured I'll try this again. A battleship steams due east at 24 km/h. A submarine 4.0 km away fires a torpedo that has a speed of 50 km/h. If the ship is seen 20º east of north, in what direction should the torpedo be fired to hit the ship? Homework Equations...

I tried the related-rate way a few posts above but I am not sure if I am doing it right.

So that means that the submarine is moving westward at 24 km/h and when the hypotenuse is 4 km, the torpedo is fired. That means we use x^2 + y^2 = c^2. d/dt (x^2 + y^2) = d/dt (c^2) which gives us 2x dx/dt + 2y dy/dt = 2c dc/dt...and since there is no change in y, the equation reduces to...

The answer is 46.8º east of north...can someone help me how to handle this problem?

Homework Statement A battleship steams due east at 24 km/h. A submarine 4.0 km away fires a torpedo that has a speed of 50 km/h. If the ship is seen 20º east of north, in what direction should the torpedo be fired to hit the ship? Homework Equations x motion of ship: x = vt x...

Well I derived this equation: v_{}0 = \Deltax \sqrt{}g / -2 (cos \phi)^2 (\Deltay - x tan\phi) With this equation you can pick any \Deltay as long as you know \Deltax and \phi.

WOW...I cannot believe I forgot to change that. I kept everything in feet...but forgot to change g. Geez, thanks a lot :). I knew my math couldn't have been wrong. :)

In the first case, the acceleration of M2 is zero because there is no friction between M1 and M2. Thus, the acceleration of M1 will not affect M2. In the second case, M2 will accelerate because there is friction between M1 and M2. If M1 accelerates, then the frictional force will cause M2 to...

It's a great problem for those who are studying motion in two and three dimensions :)