ok, now i got:
f(x)=sin(x) a=0 b=x
f(x)-f(0)= f'(c) (x-0)
sin(x) =cos(c) (x)
sin(x)/x=cos(c)
im stucked there...
i don't know what you mean with the the maximum and minimum values of cosine of any number.
i had:
f(x)=sin(x) a=-x b=x
f(x)-f(-x)= f'(c) (x+x)
sin(x) = sin(x)=cos(c) (2x)
2sin(x)=2cos(xc)
tan(x)=c
i don't know if that's right, but i don't get the result.
i would appreciate your help.
Homework Statement
-x<sin(x)<x
Homework Equations
show the inequality using the mean value theorem.
The Attempt at a Solution
i try to find c but i keep getting tan(x) as the solution.