Recent content by mathman100

ok, i think i may have discovered how to do some of these, except maybe this one : 1/Rtotal=1/R1 +1/R2 +1/R3

uncertainty equations?? can anyone help me here I'm dying over this! we did a lab and tomorrow I'm handing in my report, the last thing i have to do is find the uncertainties for my data, but i don't know what the uncertainty equations are! for example, one equation is R=V/I, or Rtotal=R1+R2+R3...

I have my original graph f, and I want to make 2 other graphs out of it (each with their own transformations.) g(x)=2g(1/2x+1) so it gets stretched vertically by 2, stretched horizontally by 2, goes left 1 and up 1. But my problem is with h(x)=2[g((x+1)/2)+1)] What are the transformations...

i don't know, now I'm lost:rolleyes: do you mean like a parabola? a linear line with a slope? how do i define the family? why can't i just sub in the known values of b and c: ax^2-x-1-a?

does anyone know?

woops, points= (1,0) and (-1,-2)

Really? Well first of all I put down the wrong 2 points (aorry, my fault) they should be (1,) and (-1,-2). I got 0=a+b+c and -2=a-b+c. I solved to get b=-1 and i think c=-1-a. I don't know how to continue!

This question has been killing me for days, : Give a family of quadratic functions of the form y=ax^2+bx+c, that passes through the following points: (1,1) and (2,0) I see how we can find the family, but how do we find the specific functions that pass through both those points? I tried making...

ok, so in one of my lectures our prof. showed us a graph, (that pretty much looked like an upside down parabola.) We had to find the area under the curve, and she told us we had to use integration. I'd never even heard of it before, and I don't understand what all the symbols mean, or how to use...

thanks everyone for your help, you're awesome!

that's what i thought at first too, but i tried doing it the other way, and using that 185, you take away the speed of the plane (-120), so 185-120 =65km/hr--- the speed of the car i guess?

Here's what i have: triangle xyz where x=sqrt12 (by using pyth.theorem), y=2, and z=4. dx/dt=? , dy/dt=0 , dz/dt=-160? x^2+y^2=z^2 x(dx/dt)+y(dy/dt)=z(dz/dt) since dy/dt=0: x(dx/dt)=z(dz/dt) *** This is where i get stuck again- i want dx/dt, but where do i put in the speed of the plane...

i'm not sure i understand- do i have enough information to sove if i know thta: a=2, da/dt=0 b=sqrt12, db/dt=? c=4, dc/dt= -160km/h then where do i use the speed of plane=120km?

ok, here is what i thought, i used related rates: triangle with sides a (height of plane=2), b (sqrt12, found by pythag.theorem) and side c (hypotenuse, =4 km, ditsance from car-plane) c'=(sqrt12*120)/4 =104 then to find theta sintheta=2/4, theta = 30 degrees 104sin(30)=b' 51 km/h=b...

A plane 2km high is flying at rate of 120 km/h due west and sees an oncoming car. The distance between them is 4km and is decresing at rate of 160 km/h. Find the speed of the car at this moment... I can't solve this! i guess the 4km is horizontal diatnce or else the plane and car would crash...