Recent content by mccoy1

  1. mccoy1

    I Energy measurement on superposition of states

    The energy of the superposition of states is not E = E1 + E2. It is E = E1 and E2. It's not the sum of the two energies.
  2. mccoy1

    I The absolute value of the frequency in quantum mechanics

    I see. I got it now. Thank you PeterDonis.
  3. mccoy1

    I The absolute value of the frequency in quantum mechanics

    I was reading Bransden's Quantum Mechanics 2nd edition, chapter 2 page 61. There,it says "It should be noted that since E =hv (v for nu), the absolute value of the frequency has no physical significance in Quantum mechanics..." Why is that? Isn't this a contradiction?
  4. mccoy1

    Spherical bessel differential function.

    I don't know why the link is not working. http://mathworld.wolfram.com/SphericalBesselDifferentialEquation.html
  5. mccoy1

    Spherical bessel differential function.

    I was looking at the above equation here: http://mathworld.wolfram.com/SphericalBesselDifferentialEquation.html Which has the following equation: {(d ²/dx²)+(d/dx)+[x²-(n+1/2)²] }z =0. In my opinion, this equation is of the order n+1/2 but the website and books claim it's of the order of a...
  6. mccoy1

    Transformation of expoential to hyperbolic

    K is a Boltzmann constant. M is magnetisation. b = beta. I meant the last one. The equation should read: exp(-MgbgH/KT) = sinh[(2S+1)x/2]/sinh(x/2) with M and x as defined above. Cheers.
  7. mccoy1

    Transformation of expoential to hyperbolic

    Sorry I have made a mistake in writing that down. The book actually have it as exp(-MgbH/KT). M = 2S+1. The book let gbH/KT be x. And then it went ahead to say exp(-MgbH/KT) = sinh[(2S+1)x/2]/sinh(x/2). Which is sinh[Mx/2]/sinh(x/2) . Sorry for the inconvenience.
  8. mccoy1

    Transformation of expoential to hyperbolic

    Homework Statement The book has it exp(-MgbH/KT) =(sinh(2S+1)x/2)/(sinh(x/2)) for M=2S+1, and x = gbH/(kt). Homework Equations The Attempt at a Solution I'd have it as cosh(Mx)-sinh(Mx). How did they get the above result? Help please. Thanks.
  9. mccoy1

    Approximation involving an exponential function

    Haa, thank you very much. That didn't pop in my head. Thanks a lot.
  10. mccoy1

    Approximation involving an exponential function

    Homework Statement I was following a derivation of some laws and I didn't get how they approximate some portion of the expression. That portion/part is exp[gbH/(2kT)]. The book says gbH/2 <<1 and therefore exp[gbH/(2kT)] = 1+gbH/(2kT). Homework Equations The Attempt at a Solution I agree with...
  11. mccoy1

    Calculating Volume of Intersection for 3 Balls with Different Centers

    It makes sense, but how do I do just that? I haven't learn that yet to be honest. I'll google it in a meanwhile. Thanks for the tip.
  12. mccoy1

    Calculating Volume of Intersection for 3 Balls with Different Centers

    Homework Statement If i have 3 balls of radii =2 and centres =(1,0,0),(0,1,0) and (0,0,1). Find the volume of the intersection of the three balls. Homework Equations The Attempt at a Solution The only method i know only works when the first ball has a centre at (0,0,0) and the...
  13. mccoy1

    Find X4 to Make {X1, X2, X3, X4} Linearly Independent

    Wow, thank you ver much Mark44. I'll try to find other vectors using that relation. I got the correct answer two days ago but it was through trial and error, which take a very long time.
  14. mccoy1

    Find X4 to Make {X1, X2, X3, X4} Linearly Independent

    Homework Statement Hi fellows, If we are given 3 vectors (e.g X1, X2, X3) in R^4, how would we find X4 such that {X1, X2, X3, X4} is a linearly independent set? Homework Equations The Attempt at a Solution I tried something like this: aX1 + bX2 + cX3 + dX4 =0, but it didn't...
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