Great, so I'm now calculating hx using hx=Nu(k/x).
Hx = 2858.206 * ((2.4x10-4) / 0.1 ) = 6.8597kWm-2K-1
= 6,859.7Wm-2K-1
Does this look along the right lines? Thank you for all your help.
Ok, reviewed scientific notation, and am now getting the below. Am I on track?
Re = 950*14*0.1 / (2.9x10-3) = 458621
Pr = 2.142 * (2.9x10-3) / (2.4x10-4) = 25.8825
Re now indicates turbulent flow so dittus-bottler correlation for nusselt number to be used:
Nu= 0.023 *(458621)0.8 *...
Thank you SteamKing. I missed the diameter mistake. I have corrected this but still get a low result.
Re=950*14*0.1/2.9x10-3 =0.4586
Pr=2.142x2.9x10-32.41x10-4 =2.588x10-7
Nu=0.332*(0.4586)0.5*(2.588x10-7)0.33 =0.00151
Hx=0.00151*(2.41x10-4/0.1) =3.6391x10-6kWm- 2K-1
Not sure if I'm getting this right, my answer seems very small, can anyone advise?
Question- butanol at a temperature of 28oC is pumped at a velocity of 14ms-1 through a 100mm diameter tube kept at a wall temp of 90oC. The properties of butanol are below. Determine the convective heat...